SOLUTION: Find the equation of the line passing through the point P(1, - 5) and perpendicular to the line 3x – 6y = 7. Write the equation in slope-intercept form.

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Question 1078901: Find the equation of the line passing through the point P(1, - 5) and perpendicular to the line 3x – 6y = 7. Write the equation in slope-intercept form.

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

the line passing through the point P(, ) and
perpendicular to the line =>=>=>

Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of , you can find the perpendicular slope by this formula:

where is the perpendicular slope


So plug in the given slope to find the perpendicular slope



When you divide fractions, you multiply the first fraction (which is really ) by the reciprocal of the second



Multiply the fractions.


So the perpendicular slope is



So now we know the slope of the unknown line is (its the negative reciprocal of from the line ). Also since the unknown line goes through (1,-5), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

where m is the slope and (,) is the given point



Plug in , , and



Distribute



Multiply



Subtract from both sides to isolate y

Combine like terms

So the equation of the line that is perpendicular to and goes through (,) is


So here are the graphs of the equations and




graph of the given equation (red) and graph of the line (green) that is perpendicular to the given graph and goes through (,)



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