SOLUTION: Divide 243 into 3 parts such that half of the first part,one-third of the second part and one-fourth of the third part are all equal.

Question 1069703: Divide 243 into 3 parts such that half of the first part,one-third of the second part and one-fourth of the third part are all equal.
Found 2 solutions by Edwin McCravy, ikleyn:
Answer by Edwin McCravy(20055) (Show Source): You can put this solution on YOUR website!

Clear of fractions and solve the system. Edwin

Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.

First part of the condition says x + y + z = 243, (1) where x is the first quantity, y is the second and z is the third. Second part of the condition gives these equalities = , (2) = (3) From (2), y = , z = = = 2x. Substitute it into (3), and you will get = 243, or 4.5x = 243. x = = 54. Then y = = 81 and z = 2x = 108.

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