SOLUTION: 2x + 5y =4 4x + 10y =1

Algebra.Com
Question 1069198: 2x + 5y =4
4x + 10y =1

Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52790)   (Show Source): You can put this solution on YOUR website!
.
2x +  5y = 4,    (1)
4x + 10y = 1.    (2)

Multiply the first equation by 2 (both sides). You will get an equivalent system

4x + 10y = 8,    (1')
4x + 10y = 1.    (2')

These equations have identical left sides, but different right sides.

It implies, that the system (1'),(2') has no solutions.

Answer. There are NO SOLUTIONS.

See the lesson
    - Geometric interpretation of the linear system of two equations in two unknowns
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Systems of two linear equations in two unknowns".



Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
Dividing both sides of the second equation by 2 gives



Now, your system of equations shown more simply is
Their slopes are equal; they represent parallel lines and will not intersect, so this system has no solution.

RELATED QUESTIONS

2x-5y=11,... (answered by jojo14344)
4x-10y=18... (answered by Fombitz)
1/2x+3/5y=-1 3/4x-7/10y=13/2 solve by any... (answered by Alan3354)
x-5y=-6... (answered by mananth)
4x-12y=6 15x4y=4 and 2x+5y=33.5... (answered by mananth)
are the lines parallel?explain. 2x+5y= -1 and 10y=... (answered by Maths68,lwsshak3)
4/5y-4=-9/10y+1 (answered by jim_thompson5910)
((2x)^3(xy)^2) + (2xy)^2(-x)^3 = (8x^3)(x^2y^2)+(4x^2y^2)(-x^3) (answered by jaya_rohith1@yahoo.com)
Solve by elimination method 3x-5y=1... (answered by mananth,tommyt3rd)