SOLUTION: Find the equation of the line perpendicular to
−2x + 9y = −5
passing through the point
(−6, 11).
(Put the answer in
y = mx + b
form.)
Algebra.Com
Question 1057306: Find the equation of the line perpendicular to
−2x + 9y = −5
passing through the point
(−6, 11).
(Put the answer in
y = mx + b
form.)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the equation of the line perpendicular to
−2x + 9y = −5 passing through the point (−6, 11).
(Put the answer in y = mx + b form.)
------
Rearrange the given equation::
y = (2x-5)/9
slope = 2/9
------
Every line perpendicular to it has slope -9/2
----------------------
y = mx + b
Substitute for x,y, and m ; solve for "b"::
11 = (-9/2)(-6) + b
11 = 27 + b
b = -16
----
Ans: y = (-9/2)x - 16
--------------------
Cheers,
Stan H.
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