SOLUTION: A chemist has a 25% and a 50% acid solution. How much of each solution should be used to form 200 mL of a 35% acid solution?
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Question 105451: A chemist has a 25% and a 50% acid solution. How much of each solution should be used to form 200 mL of a 35% acid solution?
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
.50X+.25(200-X)=.35*200
.50X+50-.25X=70
.25X=70-50
.25X=20
X=20/.25
X=80 ML OF 50% SOLUTION.
200-80=120 ML OF 30& SOLUTION.
PROOF
.50*80+.25*120=.35*200
40+30=70
70=70
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