SOLUTION: A garden is 15 ft by 13 ft. You are building a walkway around this garden that is of uniform width. The area of the garden and walkway together is 30 less than twice the area of

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Question 1053331: A garden is 15 ft by 13 ft. You are building a walkway around this garden that is of
uniform width. The area of the garden and walkway together is 30 less than twice the
area of the garden. Find the width of the walkway.

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
The type of problem is a slight variation of this kind:

rectangular outside-border - video

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
A garden is 15 ft by 13 ft. You are building a walkway around this garden that is of
uniform width. The area of the garden and walkway together is 30 less than twice the
area of the garden. Find the width of the walkway.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let "w" be the width of the walkway. 
Then the dimensions of the large rectangle are 15+2w and 13+2w.
The area of the large rectangle is the product (15+2w)*(13+2w).

The condition says

(15+2w)*(13+2w) = 2*15*13 - 30.

You need to solve this equation for w. Simplify:

15*13 + 30w + 26w + 4w^2 = 2*15*13 - 30,

4w^2 + 56w = 165,

4w^2 + 56w - 165 = 0.

Use the quadratic formula

 =  = .

 =  =  = 2.5 ft.   (Ignore the negative root).

Answer. 2.5 ft

For more similar solved problems see the lesson
    - Problems on the area and the dimensions of a rectangle surrounded by a strip
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic
"Dimensions and the area of rectangles and circles and their elements ".


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