SOLUTION: At 2 am snow started falling at a constant rate. At 10:30 am Harry began clearing his driveway at a constant rate. At 11 am when it stopped snowing the average depth of the snow on

Question 105069This question is from textbook Algebra 2 and Trig
: At 2 am snow started falling at a constant rate. At 10:30 am Harry began clearing his driveway at a constant rate. At 11 am when it stopped snowing the average depth of the snow on the driveway was 2 in. By 11:24 the driveway was clear. At what rate did the snow fall in in./hour.
I am really confused at this problem and don't even know where to start. This question is from textbook Algebra 2 and Trig

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
At 2 am snow started falling at a constant rate. At 10:30 am Harry began clearing his driveway at a constant rate. At 11 am when it stopped snowing the average depth of the snow on the driveway was 2 in. By 11:24 the driveway was clear. At what rate did the snow fall in in./hour.
:
Get some facts in our mind, and write them down:
:
No. hrs the snow fell: 11:00 - 2:00 = 9 hrs
No. hrs shoveling snow: 11:24 - 10:30 = :54 min; 54/60 = .9 hrs
No. hrs shoveling after the snowing stopped: 11:24 - 11:00 = :24 min = 24/60 = .4 hr
:
At 11 the snow was 2 in deep and at 11:24 it was gone, therefore
He shoveled at a rate of 2 in .4 hr or at a rate of 2/.4 = 5 inches/hr
:
Let x = snowfall in inches/hr:
:
Fallen snow - shoveled snow = 0
9x - .9(5) = 0
9x - 4.5 = 0
9x = +4.5
x = 4.5/9
x = .5 inches per hr
:
Did this make some sense to you? Any questions?
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