# SOLUTION: I was doing my assignment I got stuck on this problem. A repair service charges a fixed fee for a house call plus a fixed hourly rate. If a 2 hour call cost \$57 and a 4 1/2 hour

Algebra ->  Algebra  -> Linear-equations -> SOLUTION: I was doing my assignment I got stuck on this problem. A repair service charges a fixed fee for a house call plus a fixed hourly rate. If a 2 hour call cost \$57 and a 4 1/2 hour      Log On

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 Question 105067: I was doing my assignment I got stuck on this problem. A repair service charges a fixed fee for a house call plus a fixed hourly rate. If a 2 hour call cost \$57 and a 4 1/2 hour call costs \$97, what is the fixed fee for a house call. I have: 2/57=4.5/97 194=256.5 Now what?Answer by Earlsdon(6291)   (Show Source): You can put this solution on YOUR website!Let x = the fixed fee and y = the hourly rate. For the 2-hour call, you can write: 1) ...and for the 4.5-hour call, you can write: 2) You need to solve this system of equations for x, the fixed fee. Solve equation 1) for y and substitute into equation 2) then solve it for x. 1) 2) Simplify and solve for x. Multiply both sides by 2. The fixed fee is \$25.00 The hourly fee is: Substitute x = 25. The hourly fee is \$16.00