SOLUTION: Write the​ slope-intercept equation of the function f whose graph satisifies the given conditions. The graph of f passes through left parenthesis negative 4 comma 8 right

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Question 1050488: Write the​ slope-intercept equation of the function f whose graph satisifies the given conditions.
The graph of f passes through
left parenthesis negative 4 comma 8 right parenthesis(−4,8)
and is perpendicular to the line that has an​ x-intercept of
11
and a​ y-intercept of
negative 2−2.
Found 3 solutions by ewatrrr, Boreal, MathTherapy:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi  

Original Line:

(11, 0)

(0,-2) m = 2/11  m =

Line Perpendicular to that Line:  m = -11/2 (negative reciprocal)

Perpendicular Line passes thru (-4, 8)

y - 8 = (-11/2)(x + 4)  ***Using point-slope form, 

y = (-11/2)x -22 + 8

y = (-11/2)x - 14 (slope-intercept form) 

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
 x intercept of 11 is (11,0)

y-intercept of -2 is (0.-2)

The slope of that line is -2/-11 or 2/11

It passes through (0,-2), so the equation is y=(2/11)x-2 

--------------------------------

The slope of f is the negative reciprocal of 2/11 or -11/2

It has a point of (-4,8)

slope intercept form os y-y1=m(x-x1), where m is the slope, and (x1,y1) is a point

y-8=(-11/2)(x+4)

y-8=(-11/2)x-22

y=(-11/2)x+14

 

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
 

Write the​ slope-intercept equation of the function f whose graph satisifies the given conditions. 

The graph of f passes through 

left parenthesis negative 4 comma 8 right parenthesis(−4,8) 

and is perpendicular to the line that has an​ x-intercept of 

11 

and a​ y-intercept of 

negative 2−2.


 

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