SOLUTION: I need to write an equation in slope intercept form for the line that passes through the given point and is Perpendicular to the graph of the given equations. I need to show work.

Question 1048453: I need to write an equation in slope intercept form for the line that passes through the given point and is Perpendicular to the graph of the given equations. I need to show work. (-2,-2),y=-1/3x=9

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Line thru(-2,-2),perpendicular to y=-1/3x+9 , m = (-1/3)
Perpendicular Line m = 3/1 (negative reciprocal of (-1/3))
Using point-slope form,
y + 2 = 3(x+2)
y = 3x + 4 (in slope intercept form)
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