SOLUTION: five years ago a man was seven times as as old as his son.five years hence, the father will be three times as old as his son. find their present age.
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Question 1041101: five years ago a man was seven times as as old as his son.five years hence, the father will be three times as old as his son. find their present age.
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let f=father, s=son. Then:
f-5=7(s-5)
f+5=3(s+5)
f+5=3s+15
f-5=7s-35
10=-4s+50
4s=40
s=10
The son is 10; the father is 40. ☺☺☺☺
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