SOLUTION: What is the equation of the line perpendicular to 5x+2y-1=0 that goes through (-2,4)
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Question 1027997: What is the equation of the line perpendicular to 5x+2y-1=0 that goes through (-2,4)
Found 2 solutions by Alan3354, Fombitz:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
What is the equation of the line perpendicular to 5x+2y-1=0 that goes through (-2,4)
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Find the slope of the given line.
The slope of lines perpendicular is the negative inverse.
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Then use y-y1 = m*(x-x1) where m = slope and (x1,y1) is the point (-2,4)
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals.
So,
Using the point-slope form,
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