SOLUTION: Write an equation of the line satisfying the given conditions.​
Perpendicular to x−5y=4​; ​y-intercept ​(0,−5​)
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Question 1026989: Write an equation of the line satisfying the given conditions.
Perpendicular to x−5y=4; y-intercept (0,−5)
Found 2 solutions by josgarithmetic, mananth:
Answer by josgarithmetic(39628) (Show Source): You can put this solution on YOUR website!
y=mx+b
;
m neede is ----Do you know how?
;
y=-5x-5
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
1 x + -5 y = 4
Find the slope of this line
-5 y = -1 x + 4
Divide by -5
y = 1/ 5 x + - 4/5
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = 1/5
The slope of a line perpendicular to the above line will be the negative reciprocal -5
Because m1*m2 =-1
The slope of the required line will be -5
m= -5 ,point ( 0 , -5 )
Find b by plugging the values of m & the point in
y=mx+b
-5 = -0 + b
b= -5
m= -5
The required equation is y = -5 x -5
m.ananth@hotmail.ca
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