SOLUTION: What is the equation of the line that passes through the points (-1,3), and (0,1)?

Question 1023605: What is the equation of the line that passes through the points (-1,3), and (0,1)?
Found 2 solutions by josgarithmetic, Cromlix:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
y-intercept is already given. Fit the two points into slope-intercept form.

Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
Gradient = y2 - y1/x2 - x1
Gradient = 1 - 3/0 -(-1)
Gradient = -2/1
Gradient = -2
Using line equation y - b = m(x - a)
m = -2 (a,b) = (-1,3)
y - 3 = -2(x - (-1))
y - 3 = -2(x + 1)
y - 3 = -2x - 2
y = -2x - 2 + 3
y = -2x + 1
Hope this helps :-)
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