Hi
How do I find the equation of the line passing through points (1,19) and (-1,-3)
Takes two steps:
I. find slope m =
(1,19) and
(-1,-3 m = 22/2 = 11
II. Use y = mx + b and P(1,19)
y = 11x + b
19 = (11)(1) + b Substitute x and y values from P(1,19)
19-11 = b
8 = b
Then
y = 11x + 8 0r Standard form: 11x-y = -8