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2. Solve the following systems of equations by elimination. Verify the solutions.
a. r + 2s + 1 = 0
r + 5s + 28 = 0
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First, write the equation in canonical form:
r + 2s = -1, (1)
r + 5s = -28. (2)
Distract equation (1) from equation (2) (both sides).
In this way you eliminate the unknown r and obtain a singular equation for the unknown s:You will get
5s - 2s = -28 - (-1) = -27.
Hence, s = = -9.
Then from (1) r = -1 - 2s = -1 -2*(-9) = -1 +18 = 17.
Answer. The solution is r = 17, s = -9.
Please check yourself the solution. Simply substitute the found values into the original equations (1) and (2).