SOLUTION: NEED ANSWERS PLEASE PLEASE!! 1. Sketch a graph of the relation y + 4 = 2(x – 3). Explain the procedure used. 2. Sketch a graph of the linear relation 8x + 2y = 24. Explain

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Question 1018654: NEED ANSWERS PLEASE PLEASE!!
1. Sketch a graph of the relation y + 4 = 2(x – 3). Explain the procedure used.
2. Sketch a graph of the linear relation 8x + 2y = 24. Explain the procedure.
3. Determine the value of B such that the line defined by 8x + By + 92 = 0 passes through the point (-4,12).
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
1:

,y+4=2(x-3), is in point-slope form. This line has slope and includes
the point (-4,3).



2:

Standard Form equation,

Now as slope-intercept form, .
Slope is and y-intercept is 12.



3:

must pass through (-4,12). Solve for B.


but this pathway is not necessary.
-
Instead, try solving for B and substitute the point needed.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

NEED ANSWERS PLEASE PLEASE!!
1. Sketch a graph of the relation y + 4 = 2(x – 3). Explain the procedure used.
2. Sketch a graph of the linear relation 8x + 2y = 24. Explain the procedure.
3. Determine the value of B such that the line defined by 8x + By + 92 = 0 passes through the point (-4,12).
Nos. 1 and 2:

1) Substitute 0 for x, and solve for y to determine the y-intercept point

2) Substitute 0 for y, and solve for x to determine the x-intercept point

3) Join the points to get the graph



No. 3:

8x + By + 92 = 0 ------ Substituting (- 4, 12) into equation

8(- 4) + 12B + 92 = 0

- 32 + 12B + 92 = 0

60 + 12B = 0

12B = - 60

, or  

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