SOLUTION: a. Is the point (-1, 1) on the graph of 〖(x-1)〗^2+〖(y-3)〗^2=0 ?
Show work.
b. Find the x and y intercepts for the graph of 〖(x-1){
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Question 1015646: a. Is the point (-1, 1) on the graph of 〖(x-1)〗^2+〖(y-3)〗^2=0 ?
Show work.
b. Find the x and y intercepts for the graph of 〖(x-1)〗^2+〖(y-3)〗^2=0
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
A).
.
It is difficult to discern your equation.
If this is not your equation, clarify it and re-post your question.
.
.
Point (-1,1)
x=-1, y=1
Put these values in the equation, and evaluate to see if it is true.
.
. False. The point is not on the graph.
.
B).
x intercept: y=0
.
=+/-
No x intercept.
.
y intercept: x=0
.
=+/-
No y intercept.
.
Graph of the equation is a circle with center at (1,3) and zero radius.
The only real number solution is point (1,3).
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