SOLUTION: For what value of a are the graphs of 6y=-2x+4 and 2y=ax-5perpendecular

Question 1003061: For what value of a are the graphs of 6y=-2x+4 and 2y=ax-5perpendecular

Found 2 solutions by MathLover1, mananth:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

the graphs of and will be perpendicular if their slopes are negative reciprocals to each other
so, write first equations in the slope-intercept form

as you can see, the slope is
now to find the slope of the perpendicular line , find negative reciprocal of which will be
plug in for

so, your perpendicular line is:

see it on a graph:

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
6y=-2x+4 and 2y=ax-5perpendecular

6y=-2x+4
y=-2/6 x +2/3
y = (-1/3)x +2/3 slope = (-1/3)
2y=ax-5
y= (a/2)x -5/2 slope = (a/2)
For them to be perpendicular
(-1/3) = a/2
a= -2/3

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