# SOLUTION: The time, in minutes, taken to cook a chicken, C, is linearly related to the weight, in kilograms, of the chicken, k. It takes 40 minutes to cook a 1.4kg chicken and 50 minutes to

Algebra ->  -> SOLUTION: The time, in minutes, taken to cook a chicken, C, is linearly related to the weight, in kilograms, of the chicken, k. It takes 40 minutes to cook a 1.4kg chicken and 50 minutes to       Log On

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 Click here to see ALL problems on Linear-equations Question 707063: The time, in minutes, taken to cook a chicken, C, is linearly related to the weight, in kilograms, of the chicken, k. It takes 40 minutes to cook a 1.4kg chicken and 50 minutes to cook a 1.8kg chicken. Find the linear equation relating cooking time, C, with the weight of the chicken, k to find how long it would take to cook a 1.7kg chicken. how would i solve this equation? as far asi can figure you would go C=C*k-1.7Answer by nerdybill(7090)   (Show Source): You can put this solution on YOUR website!The time, in minutes, taken to cook a chicken, C, is linearly related to the weight, in kilograms, of the chicken, k. It takes 40 minutes to cook a 1.4kg chicken and 50 minutes to cook a 1.8kg chicken. Find the linear equation relating cooking time, C, with the weight of the chicken, k to find how long it would take to cook a 1.7kg chicken. how would i solve this equation? as far asi can figure you would go C=C*k-1.7 . The problem gives you two points: (1.4, 40) and (1.8, 50) . Determine the equation from the two points. Slope: m = (y2-y1)/(x2-x1) m = (50-40)/(1.8-1.4) m = (10)/(.4) m = 25 Now, use the slope (25) and one of the two points, say (1.4, 40) and plug it into the "point-slope" form: y - y1 = m(x - x1) y - 40 = 25(x - 1.4) y - 40 = 25x - 35 y = 25x + 5 . So, now we can answer: Find the linear equation relating cooking time, C, with the weight of the chicken, k: c = 25k + 5 and, to find how long it would take to cook a 1.7kg chicken. c = 25(1.7) + 5 = 47.5 minutes