# SOLUTION: Trying to change the following equation into slope intercept form. 3/4x-3y=-5 I first moved the 3/4 x to the other side to get -3y=-3/4x-5 I am just wondering how you then

Algebra ->  -> SOLUTION: Trying to change the following equation into slope intercept form. 3/4x-3y=-5 I first moved the 3/4 x to the other side to get -3y=-3/4x-5 I am just wondering how you then      Log On

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 Question 703807: Trying to change the following equation into slope intercept form. 3/4x-3y=-5 I first moved the 3/4 x to the other side to get -3y=-3/4x-5 I am just wondering how you then get the y by itself? I would divide by -3 but how do I divide -3/4 by -3? Or, do I need to get rid of the fraction to start off? If so, how do I do that? ThanksFound 2 solutions by Alan3354, stanbon:Answer by Alan3354(34679)   (Show Source): You can put this solution on YOUR website!Trying to change the following equation into slope intercept form. 3/4x-3y=-5 I first moved the 3/4 x to the other side to get -3y=-3/4x-5 I am just wondering how you then get the y by itself? I would divide by -3 but how do I divide -3/4 by -3? -------------- (-3/4)/(-3) = 1/4 ---- --> y = (1/4)x + 5/3 Answer by stanbon(60778)   (Show Source): You can put this solution on YOUR website!Trying to change the following equation into slope intercept form. 3/4x-3y=-5 ----- Since you want y to be positive, add 3y to both sides to get: 3y = (3/4)x + 5 ---- Divide thru by 3 to get: y = (1/4)x + (5/3) ====== That is the slope-intercept form. Cheers, Stan H. =============