# SOLUTION: I don't really get how to solve this problem. Chris has a jar with dimes and quarters in it. The jar has 7 more quarters in it than it has dimes. If the total value of the coin

Algebra ->  -> SOLUTION: I don't really get how to solve this problem. Chris has a jar with dimes and quarters in it. The jar has 7 more quarters in it than it has dimes. If the total value of the coin       Log On

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 Click here to see ALL problems on Linear-equations Question 589635: I don't really get how to solve this problem. Chris has a jar with dimes and quarters in it. The jar has 7 more quarters in it than it has dimes. If the total value of the coin is \$5.60, how many quarters are in the jar? This was how i did it, but it didn't seem right. 25(x+7) = 560 25x+175=560 25x=560-175 25x=385 x=385/25 x=15.4Answer by John10(297)   (Show Source): You can put this solution on YOUR website!Hello:) You will need to set up two equations for the linear system and solve the variables. Let d be the number of dimes and q be the number of quarters The total value is \$5.6: 0.1d + 0.25q = 5.6 The jar has 7 more quarters in it than it has dimes: q = d + 7 So we have two equations: 0.1d + 0.25q = 5.6 q = d + 7 Solve the system, you will find the number of quarter and dimes in the jar. Hope it helps you! John10:)