# SOLUTION: What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 2x + y - 1 = 0? 2x - y - 4 = 0 2x + y - 4 = 0 2x + y + 4 = 0

Algebra ->  -> SOLUTION: What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 2x + y - 1 = 0? 2x - y - 4 = 0 2x + y - 4 = 0 2x + y + 4 = 0      Log On

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 Click here to see ALL problems on Linear-equations Question 553571: What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 2x + y - 1 = 0? 2x - y - 4 = 0 2x + y - 4 = 0 2x + y + 4 = 0Answer by nerdybill(7090)   (Show Source): You can put this solution on YOUR website!What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 2x + y - 1 = 0? put: 2x + y - 1 = 0 into "slope-intercept" form: 2x + y - 1 = 0 2x + y = 1 y = -2x + 1 now, we know the slope is -2 "parallel" lines must have the same slope use -2 and (1,2) to populate "point-slope" form: y - y1 = m(x - x1) y - 2 = -2(x - 1) y - 2 = -2x + 2 y = -2x + 4 (slope-intercept form) 2x + y -4 = 0 (standard form) (answer)