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Arrange the above equation in slope-intercept form
y=3/4(x)+3/8 , passing through the point (-3,-15)
Equation of the line slope-intercept form
Slope of given line m = 3/4
Since the required line is perpendicular to the given line the sign of this line will be opposite to sign of given line's slope and it will be reciprocal to the slope of the given line
slope (m) of required line will be = -4/3
Now we have a slope (-4/3) and we have a point (-3, -15)
We can easily find the equation of the line either by slope-intercept form or by Point slope-form.
y=-15, x=-3, m= -4/3 and we have to find b
Plug in the value in the equation of line
Put the value m and b in (1)
Equation of the line passing through (-3, -15) and perpendicular to line y=3/4(x)+3/8) is
Use Point slope form
Plug in the values m = -4/3, x=-3, y=-15
y=-4x/3 - 19