# SOLUTION: In Exercises 43-52, find the general form of the equation of the line that passes through the points. Use a graphing utility to sketch the line 44.(4,3),((-4,-4)

Algebra ->  -> SOLUTION: In Exercises 43-52, find the general form of the equation of the line that passes through the points. Use a graphing utility to sketch the line 44.(4,3),((-4,-4)      Log On

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 Click here to see ALL problems on Linear-equations Question 49763This question is from textbook PreCalculus with limits agraphing approach : In Exercises 43-52, find the general form of the equation of the line that passes through the points. Use a graphing utility to sketch the line 44.(4,3),((-4,-4)This question is from textbook PreCalculus with limits agraphing approach Answer by tutorcecilia(2152)   (Show Source): You can put this solution on YOUR website!(4,3),(-4,-4) [Given points] m =(y2-y1)/(x2-x1) [To find the slope, use the slope formula since two points are given] . m =(-4-3)(-4-4) [Plug-in the values] m = -7/-8 = 7/8 [The slope of the line] . Ax+By=C [General Form of the equation of the line] (y-y1) = m(x-x1) [Use the point-slope formula since you now have the slope and two points] . (y-3) = (7/8)(x-4) [Plug-in the values for the (m) and one of the points (4,3)] y-3 = (7/8)x - (7/8)(4) [Simplify] y-3 = (7/8)x -7/2 [Isolate all of the variables on one side of the equation] y-3+3 = (7/8)x-(7/2)+3 y = (7/8)x-(1/2) y -(7/8)x = (7/8)x-(7/8)x -(1/2) y -(7/8)x = -1/2 [Re-arrange the terms] -7/8x + y = -1/2 [General Form of the equation of the line][Final answer] . Check by plugging the values of the points back into the General Form]