# SOLUTION: Can I get help with the following problem please!! Find the equation of the tangent line to the curve y = (4x + 1) / (3x - 2) at the point (1, -2). (Write the line in y = mx + b f

Algebra ->  -> SOLUTION: Can I get help with the following problem please!! Find the equation of the tangent line to the curve y = (4x + 1) / (3x - 2) at the point (1, -2). (Write the line in y = mx + b f      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Mathway solves algebra homework problems with step-by-step help!

 Question 439372: Can I get help with the following problem please!! Find the equation of the tangent line to the curve y = (4x + 1) / (3x - 2) at the point (1, -2). (Write the line in y = mx + b form) Found 3 solutions by stanbon, robertb, Alan3354:Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!Can I get help with the following problem please!! Find the equation of the tangent line to the curve y = (4x + 1) / (3x - 2) at the point (1, -2). (Write the line in y = mx + b form) ----------------------------------------- f'(x) = [(3x-2)(4)-(4x+1)/(3)]/(3x-2)^2 --- f' = [(12x-8)-(4x+1)]/(3x-2)^2 ---- f' = [8x-9]/[3x-2]^2 --- f'(1,-2) = [8-9]/[3-2]^2 = 1/1 = 1 ----- Form: y = mx + b -2 = 1*1 + b b = -3 ---- Equation of the tangent line at (1,-2): y = x-3 ================== Cheers, Stan H. Answer by robertb(4012)   (Show Source): You can put this solution on YOUR website! At (1, -2), , the slope of the tangent line. ==> Equation of the tangent line is y--2 = -11(x-1), or y+2 = -11x + 11, or y = -11x + 9. Answer by Alan3354(34677)   (Show Source): You can put this solution on YOUR website!The point (1,-2) is not on the graph. At x = 1, y = 5