# SOLUTION: Write an equation of the line containing the given point and perpendicular to the given line. (0,9) 4x+7y=2

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 Question 437402: Write an equation of the line containing the given point and perpendicular to the given line. (0,9) 4x+7y=2Found 2 solutions by stanbon, ewatrrr:Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!Write an equation of the line containing the given point and perpendicular to the given line. (0,9) 4x+7y=2 --- Find the slope of the given line: y = (-4/7)x+(2/7) slope = -4/7 ---------------------- Any perpendicular line must have slope = 7/4 ------- y-intercept is 9 ----- Required equation is y = (7/4)x+9 ===================================== Cheers, Stan H. =========== Answer by ewatrrr(11173)   (Show Source): You can put this solution on YOUR website! ``` Hi Using the standard slope-intercept form for an equation of a line y = mx + b where m is the slope and b the y-intercept. line containing point (0,9) and perpendicular to 4x+7y=2 4x+7y=2 OR y = (-4/7)x + 2/7 slope = (-4/7) New Line: slope is the negative reciprocal of (-4/7) y = (7/4)x + b |b is the y-intercept (0,9) 9 = b y = (7/4)x + 9 ```