# SOLUTION: How do I properly graph this equation on algebra.com? x-4y=-8 I know that rise=2 run=8 and slope=1/4 My original task was to find the rise, run, and slope and then write in

Algebra ->  -> SOLUTION: How do I properly graph this equation on algebra.com? x-4y=-8 I know that rise=2 run=8 and slope=1/4 My original task was to find the rise, run, and slope and then write in      Log On

 Ad: Mathway solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Question 273601: How do I properly graph this equation on algebra.com? x-4y=-8 I know that rise=2 run=8 and slope=1/4 My original task was to find the rise, run, and slope and then write in standard form after looking at a graph. that had a line on it. I understand that Ax+By=C I don't quite understand what Ax is, Bx, or C. The original problem didn't have the standard form answer of x-4y=-8, that was in the back of my text book. I have included what I thought was the correct graph, but all it did was draw a horizontal line. So, if you can show me what I am missing in the computer formula I would appreciate it. I would love for someone to explain how to get the standard form out of the given information graph( 300, 200, -6, 5, -10, 10, x-4y=-8) Answer by Theo(3556)   (Show Source): You can put this solution on YOUR website!standard for of the equation for a line is Ax + By = C A is the coefficient of the x variable. B is the coefficient of the y variable. C is the constant. your equation is: x - 4y = -8 in your equation, which is in standard form, .... A = 1 B = -4 C = -8 to graph this equation, you need to solve for y. at the same time you will be putting this equation into the slope-intercept form of it. subtract x from both sides of this equation to get -4y = -x - 8 divide both sides of this equation by -4 to get y = (1/4)*x + 2 the slope intercept form of the equation for a line is y = mx + b where m is the slope and b is the y intercept. in your equation, the slope is (1/4) and the y intercept is 2. when you graph in algebra.com, you have to solve for y as we just did. you then enter ONLY the right side of the equation. you do not enter the y. to graph your equation you would put the following between the starting 3 brackets and the ending 3 brackets. ``` graph (600,600,-10,10,-10,10,(1/4)*x + 2) ``` the first 600 is the width of the graph. the second 600 is the height of the graph. the first -10 is the low end of the x-axis. the first 10 is the high end of the x-axis. the second -10 is the low end of the y-axis. the second 10 is the high end of the y-axis. the right side of your equations after you have solved for y goes next. here's what the graph of your equation looks like. I just took that expression and enclosed it in the brackets. assuming you were given the equation in slope intercept form to start with, then you were given: y = (1/4)x + 2 to convert this to standard form, you want to get the x and y on the left side of the equation and the constant term on the right side of the equation. you would multiply both sides of the equation by 4 to get: 4y = x + 8 you would then subtract x from both sides of the equation to get: -x + 4y = 8 that's the standard form of the equation where A = -1 and B = 4 and C = 8 if you multiply both sides of this equation by -1 you would get: x - 4y = -8 that's the standard form of the equation where A = 1 and B = -4 and C = -8 the two equations: -x + 4y = 8 x - 4y = -8 are equivalent.