# SOLUTION: I am trying to help my daughter. she was learning ax(squared) + bx + c = y, which she understands. However she was given vertex (2, -3) contains points (-1,-12) y-k=a(x-h)

Algebra ->  -> SOLUTION: I am trying to help my daughter. she was learning ax(squared) + bx + c = y, which she understands. However she was given vertex (2, -3) contains points (-1,-12) y-k=a(x-h)      Log On

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 Click here to see ALL problems on Linear-equations Question 254282: I am trying to help my daughter. she was learning ax(squared) + bx + c = y, which she understands. However she was given vertex (2, -3) contains points (-1,-12) y-k=a(x-h)squared she has to find "a" then plug in to the vertix form to find the ax formFound 2 solutions by nerdybill, richwmiller:Answer by nerdybill(7090)   (Show Source): You can put this solution on YOUR website!given vertex (2, -3) contains points (-1,-12) y-k=a(x-h)squared she has to find "a" then plug in to the vertex form to find the ax form . The "vertex form" of a parabola is: y= a(x-h)^2+k http://www.mathwarehouse.com/geometry/parabola/standard-and-vertex-form.php . y-k = a(x-h)^2 where (h,k) is the vertex . Plug in what the problem gave: vertex (2, -3) contains points (-1,-12) y-k = a(x-h)^2 Plugging in (2, -3) we get: y-(-3) = a(x-2)^2 Plugging in our point (-1,-12) -12-(-3) = a(-1-2)^2 -12+3 = a(-3)^2 -9 = a(9) -1 = a Answer by richwmiller(10281)   (Show Source): You can put this solution on YOUR website!(h,k) are the vertex coordinates So plug those in (2, -3) for (h,k) (-1,-12) for (x,y) y-k=a(x-h)^2 -12-(-3)=a(-1-2)^2 Mind your signs -12+3=a(-3)^2 remember (-3)^2=+9 -9=a+(9) -1=a