Two planes make a 1000 mile flight, one flying 75 miles per hour faster than the other. The quicker plane makes the trip 3 hour faster. lHow long did it take the slower oplane to complete the flight?
Let time taken by slower plane be T
Then time taken by faster plane = T – 3
Speed of slower plane, equals speed of faster plane, less difference in speeds, OR
1,000(T – 3) = 1,000T – 75T(T – 3) ------- Multiplying by LCD, T(T – 3)
(T - 8)(T + 5) = 0
T, or time taken by slower plane = hours OR T = - 5 (ignore)