SOLUTION: the points A(3,2) and B(2,-3) are equidistant from a point P(x,y). find the relation beween x and y.

Question 942849: the points A(3,2) and B(2,-3) are equidistant from a point P(x,y). find the relation beween x and y.
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
Perpendicular Bisector of AB.

Slope for AB is . The line perpendicular to AB must have slope .

Midpoint of AB is

and
.
As ordered pair of coordinates, this midpoint is (5/2,-1/2).

The line for any point P will be using POINT-SLOPE form for equation of a line. Simplify and put into whatever form you want.
RELATED QUESTIONS
Find a point (x,y) equidistant from points (2,-7), (-3,-8) and (-5,9) (answered by ikleyn,Alan3354)

which equation represents the set of all points equidistant from y=-3 and y=5? a. y=2... (answered by rfer)

Find a point (x,y) equidistant from point (-3,8) and the line... (answered by Alan3354)

A point (x,y() is equidistant from the line x=2y=3 and the point (2,0) . Find an equation (answered by ikleyn)

Two points have coordinates A(1,-3) and B(-3,5).Find the equation of the perpendicular... (answered by ewatrrr)

a) a point P moves so that it is equidistant from the points A(1,2)and B(-2,-1). find (answered by Alan3354)

The Point P(2,y) equidistant from point F(3,0) and the line with equation x=-3/2. What... (answered by josgarithmetic,ikleyn)

If the point P(x,y) is equidistant from the points A(a+b,b-a) and B(a-b,a+b). Prove that... (answered by Fombitz)