SOLUTION: A model rocket is shot vertically upward with an initial velocity of 288 ft./sec. The function given by h(t) = -16t2 + 128t relates the rocket�s height h(t) in feet to the time t a

Question 910873: A model rocket is shot vertically upward with an initial velocity of 288 ft./sec. The function given by h(t) = -16t2 + 128t relates the rocket�s height h(t) in feet to the time t after launch, in seconds. Find h(0) Find h(5) Find the t-intercepts and interpret their meaning in the context of the problem Find the times at which the rocket is at a height of 1152 feet.
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
the initial speed doesn't match the function.
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PS Use ^ (Shift 6) for exponents.
eg, -16t^2
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Also, that's not a rocket, it's a projectile.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
h(t) = -16t^2 + 288t
h(t) = -16(t-9)^2 + 1296 Pt(9,1296) max point
....
0 = -16(t-4)^2 + 1296
16(t-4)^2 = 1296
(t-4)^2 = 81
t = 4 � 9
t-intercepts: -5, 13
....
h(0) = 0
h(5) = plug and play
....
1152 = -16t^2 + 288t
16t^2 - 288t +1152 = 0
t^2 -18t + 72
(t-12)(t-6) = 0
t is 6, 12

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