SOLUTION: I have a problem that has thrown me for a loop. I am to find all values of y such that the distance between (3,y) and (-2,9) is 12. I tried to solve this problem by using the dista

Question 89454: I have a problem that has thrown me for a loop. I am to find all values of y such that the distance between (3,y) and (-2,9) is 12. I tried to solve this problem by using the distance formula (X1,Y1)and (X2,Y2). Which looks like this d=the square root of (X2-X1)2 + (Y2-Y1)2 ***this is all under the square root symble and the 2 are squares**
(-2-3)2+(3-y)2 remember the 2's are sqrares and the problem is under the sqrare root symbole
(5)2+ (3-y)2
100+9-y2
109-Y2
I'm not sure if I am on the right path. Please help!
(sorry i do not know how to put the root symbole or make the 1 by the X and Y small on the computer)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find all values of y such that the distance between (3,y) and (-2,9) is 12.
---------
d = sqrt((3--2)^2 + (y-9)^2)
12 = sqrt( 25 + (y-9)^2)
144 = 25 + (y-9)^2
119 = (y-9)^2
y = sqrt119 +9 or y = -sqrt119+9
y=19.909 or y= -1.909
========
Cheers,
stan H.
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