SOLUTION: Missing coordinate A(-3,2) , B(x,3) , c(4,5) if AB=BC , Find the value of x???

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Question 885250: Missing coordinate A(-3,2) , B(x,3) , c(4,5) if AB=BC , Find the value of x???
Found 2 solutions by richwmiller, algebrapro18:
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
(x,3) is not on the same line as A(-3,2) C(4,5) so we cannot just find the midpoint
The distance (denoted by d) between two points in two dimensions is given by the following formula:

sqrt((4-x)^2 + (5-3)^2)=sqrt((-3-x)^2 + (2-3)^2)
x = 5/7

Answer by algebrapro18(249)   (Show Source): You can put this solution on YOUR website!
To find x we need to find the distance between A and B and the distance between B and C. We can then set the two distances equal to each other and solve for x, since AB=BC.

So finding the distance between A and B we get:







That's as simplified as that can get. So now we find the distance between B and C:







So now we can set AB = BC and solve for x.
= square both sides to get rid of the square root
Subtract (x2-8x+20) from both sides
combine like terms
add 10 to both sides
divide both sides by 14
x = 10/14 = 5/7

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