SOLUTION: the area of a rectangle is 27yd^2,and the length of the rectangle is 3yd less than twice the width.Find the dimensions
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Question 879237
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the area of a rectangle is 27yd^2,and the length of the rectangle is 3yd less than twice the width.Find the dimensions
Found 2 solutions by
josgarithmetic, ewatrrr
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Answer by
josgarithmetic(39617)
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L=-3+2w and wL=27.
Substitution gives a quadratic equation, and one value will make sense but the other value will not...
Answer by
ewatrrr(24785)
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Hi,
.
A = Lw = (2w-3)w = 27yd^2
2w^2 - 3w - 27 = 0
(2w -9)(w + 3) = 0, w = 9/2yd and L = 6yd
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