SOLUTION: A parallelogram has coordinates O(0,0), A(7,1), B(4,5) and C(-3,4) Use the midpoint formula to show that the diagonals of OABC bisect each other

Algebra.Com
Question 85379: A parallelogram has coordinates O(0,0), A(7,1), B(4,5) and C(-3,4)
Use the midpoint formula to show that the diagonals of OABC bisect each other

Answer by scianci(186)   (Show Source): You can put this solution on YOUR website!
Locate the midpoint of diagonal OB: ((0 + 4)/2 , ((0 + 5)/2) = (2 , 2.5)
Then locate the midpoint of diagonal AC: ((7 - 3)/2 , (1 + 4)/2) = (2 , 2.5)
Since they have the same midpoint, they bisect each other.

RELATED QUESTIONS

Okay I have to graph the points A(-5,0) , B(3, 2) C(5, 6) and D(-3 4). Then show that... (answered by rothauserc)
The vertices of triangle ABC are A(-3, 3), B(2, -7) and C(0, 4). Use the midpoint formula (answered by stanbon)
A parallelogram has vertices (5,0), (3,-3), (-4,-3) and (-2,0). The diagonals of the... (answered by ikleyn)
The diagonals of quadrilateral EFGH intersect 0(0, 3) has vertices a parallelogram ? E(1, (answered by ikleyn)
The diagonals of quadrilateral ABCD intersect at E(- 1, 4) . ABCD has vertices at A(1, 7) (answered by jim_thompson5910,MathLover1,ikleyn)
The vertices of parallelogram ABCD are A(2, 4), B(0, 0), C(6, 2), and D(8, 6). Find the... (answered by ewatrrr)
Could someone help? - The vertices of a parallelogram are A(-4,-1),B(5,-6), C(11,-3) and (answered by nycsub_teacher)
The coordinates of of A are (k, 2k) in OABC, where K>0. length of OA is root 80 units.... (answered by greenestamps)
let O(0,0), A(6,0), B(6,6), c(0,6) be the vertices of a square OABC, and Let M be the... (answered by greenestamps)