SOLUTION: Find the distance between the two parallel lines given by the equation: 5x-4y=22 and -75x=150-60y the instructions given by the teacher were: 1. put both equations in y=mx+b fo

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Question 849726: Find the distance between the two parallel lines given by the equation: 5x-4y=22 and -75x=150-60y
the instructions given by the teacher were:
1. put both equations in y=mx+b form
2. find a point (x,y) on either equation
3. find equation of the perpendicular line that passes through (x,y)
4. use systematic equation to solve with equation 3 (the new one) and the one that wasn't used to get the point in step 2
5. calculate with distance formula
I don't know how to continue after solving both equations for y=mx+b

Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Find the distance between the two parallel lines given by the equation: 5x-4y=22 and -75x=150-60y
----------------
5x-4y=22 --> y = (5/4)x - 11/2
-75x=150-60y --> y = (5/4)x + 5/2
------------
y = (5/4)x - 11/2
(0,-11/2) is a point
Perpendicular thru the point --> y = (-4/5)x - 11/2
-----
y = (-4/5)x - 11/2 = (5/4)x + 5/2
-16x - 110 = 25x + 50
x = -160/41
y = 640/205 - 11/2 = 256/82 - 451/82 = -195/82
Intersection at (-160/41,-195/82)
--------------

d =~ 4.95

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
5x-4y=22 and -75x=150-60y

1. put both equations in y=mx+b form
2. find a point (x,y) on either equation
3. find equation of the perpendicular line that passes through (x,y)
4. use systematic equation to solve with equation 3 (the new one) and the one that wasn't used to get the point in step 2
5. calculate with distance formula

(The statement of your number 4 is not in the best wording).

BOTH EQUATIONS INTO SLOPE-INTERCEPT FORM

----first equation
-




----second equation

PICK ANY POINT ON ONE EQUATION
y=(5/4)x+5/2
Let x=2.
y=(5/4)*2+5/2
y=5/2+5/2
y=5.
Point picked is (2, 5).

LINE PERPENDICULAR CONTAINING (2, 5):
Arbitrary choice to use point-slope formula.
Want slope .



----Perpendicular to both of the given equations

INTERSECTION OF and :
Obvious formulas for y are expected equal if the two equations intersect.

Multiply members by 20 which is LCD.


(25+16)x=110+132=242


-
Find y.





-
POINT on first equation is ( 242/41, 483/41 ).


FINDING DISTANCE BETWEEN THE TWO FOUND POINTS
Step 5 on your list.
You want to use the distance formula to determine or find what is the distance between ( 242/41, 483/41 ) and (2, 5).
Very possibly, if you would try to make a graph of the two given lines, you MIGHT find more convenient set of points to use, such as to pick a point on either line and possibly have a more convenient point on the other line, intersecting also a more convenient perpendicular to both.
-
Distance is

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