SOLUTION: the length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the length of the base. If the perimeter is 29cm, find the length of one of the equal legs.

Question 84241: the length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the length of the base. If the perimeter is 29cm, find the length of one of the equal legs.
Answer by vertciel(183) (Show Source): You can put this solution on YOUR website!
Hello,
We'll denote variables for the unknowns:
Base = x
Length = 8cm less than 4 times the length of the base
= 4x - 8
Perimeter = sum of all sides
x + 4x - 8 + 4x - 8 = 29
Find x, substitute it into the base and length and you have your answers.
RELATED QUESTIONS
please help. The length of one of the equal legs of an isosceles triangle is 8cm less... (answered by Earlsdon)

The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the (answered by stanbon)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by venugopalramana)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by Paul)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by checkley71)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by Nate)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by algebrapro18)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by checkley71)