SOLUTION: what is the length of the major axis of the ellipse 3x(to the second power) + 4y(to the second power)=12

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Question 83304: what is the length of the major axis of the ellipse
3x(to the second power) + 4y(to the second power)=12
Found 2 solutions by stanbon, dolly:
Answer by stanbon(48564) (Show Source):
You can put this solution on YOUR website!
what is the length of the major axis of the ellipse
3x(to the second power) + 4y(to the second power)=12
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Divide thru by 12 to get:
(x^2)/4 + (y^2)/3 = 1
a^2 = 4
a = 2
2a = 4
The length of the major axis is 2a = 4
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Cheers,
Stan H.

Answer by dolly(163) (Show Source):
You can put this solution on YOUR website!
Given equation of the ellipse is 3x^2 + 4y^2 = 12
Dividing by 12 throughout,
3x^2/12 + 4y^2/12 = 12/12
==> x^2/4 + y^2/3 = 1
This is of the form x^2/a^2 + y^2/b^2 = 1
On comparing we get a = 2
So length of major axis = 2a
= 4