SOLUTION: I need help with this problem...The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the length of the base. If the perimeter is 29cm, find the len

Question 78700: I need help with this problem...The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the length of the base. If the perimeter is 29cm, find the length of one of the equal legs.
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
B=THE BASE
SIDE=(4B-8). THUS WE HAVE THE FOLLOWING PERIMETER EQUATION IS:
SIDE+SIDE+BASE=PERIMETER
4B-8+4B-8+B=29
9B=29+16
9B=45
B=45/9
B=5 CM FOR THE BASE.
SIDE=4*5-8=20-8=12 LENGTH FOR THE TWO SIDES.
PROOF
12+12=5=29
29=29

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