SOLUTION: The distance a spring stretches varies directly as the weight, of the object hanging from the spring and inversely and the cubic root of the thickness of the spring. A weight of 1

Question 762652: The distance a spring stretches varies directly as the weight, of the object hanging from the spring and inversely and the cubic root of the thickness of the spring. A weight of 100 pounds stretches a 0.5 inches thick spring by 3 inches. How far will a weight of 150 pounds stretch a spring that is 0.7 inches thick?
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
D = kW/cubic root of T
k = constant of variation
To find k, use information given.
3 = k100/0.794
k = (3 * 0.794)/100
k = 0.024 (3 decimal places)
Formula:
D = (0.024 * W)/cubic root of T
D = (0.024 * 150)/0.888
Distance = 4.05 inches
Hope this helps.
:-)
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