SOLUTION: In the standard (x,y) coordinate plane, what are the coordinates of the center of the circle with equation ( x-^5)2 exponent + ( y-1)2 power =1?

Question 755833: In the standard (x,y) coordinate plane, what are the coordinates of the center of the circle with equation ( x-^5)2 exponent + ( y-1)2 power =1?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
In the standard (x,y) coordinate plane, what are the coordinates of the center of the circle with equation ( x-^5)2 exponent + ( y-1)2 power =1?--------
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( x-^5) I don't know what that means.
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Use ^ for exponents, eg,
( x-5)^2 + ( y-1)^2 = 1 is a circle.
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