SOLUTION: please help me solve this equation What is the equation of the line that passes through ( 1,5) and (4,11)?

Question 746863: please help me solve this equation
What is the equation of the line that passes through ( 1,5) and (4,11)?
Found 2 solutions by Cromlix, tiiaraa:
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
First find the gradient => y2 - y1/ x2 - x1
= 11 - 5/ 4 - 1
= 6/3
= 2 = m
Next use y - b = m(x - a)
Taking one of your points (1,5)
y - 5 = 2(x - 1)
y = 2x - 2 + 5
y = 2x + 3
Answer by tiiaraa(1) (Show Source): You can put this solution on YOUR website!
the formulae to calulate the equation of line is
y-y1 = y2-y1/x2-x1 (x-x1)

where x1,y1 is 1,5
and x2,y2 is 4,11
y-5 = 11-5/4-1 (x-1)
= 6/3 (x-1)
= 2 (x-1)
y-5 = 2x - 2
hence, 2x-y+3=0 is required equation.

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