SOLUTION: Two cars leave towns 640 kilometers apart at the same time and travel toward each other. One car's rate is 10 kilometers per hour more than the other's. If they meet in 4 hours, wh

Question 685863: Two cars leave towns 640 kilometers apart at the same time and travel toward each other. One car's rate is 10 kilometers per hour more than the other's. If they meet in 4 hours, what is the rate of the faster car?
Found 2 solutions by lwsshak3, stanbon:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Two cars leave towns 640 kilometers apart at the same time and travel toward each other. One car's rate is 10 kilometers per hour more than the other's. If they meet in 4 hours, what is the rate of the faster car?
**
let x=rate of speed of faster car
x-10=rate of speed of slower car
distance=rate of speed*travel time
4x+4(x-10)=640
4x+4x-40=640
8x=680
x=85
rate of speed of faster car= 85km/hr
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two cars leave towns 640 kilometers apart at the same time and travel toward each other. One car's rate is 10 kilometers per hour more than the other's. If they meet in 4 hours, what is the rate of the faster car?
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Slower car DATA:
time = 4 hrs ; rate = x kmh ; distance = 4x km
----
Faster car DATA:
time = 4 hrs ; rate = x+10 kmh ; distance = 4x+40 km
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Equation:
distance + distance = 640 km
4x + 4x+40 = 640
8x = 600
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x = 75 kmh (slower car rate)
x+10 = 85 kmh (faster car rate)
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Cheers,
Stan H.
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