SOLUTION: Find the equation of the locus of the points which are equidistant from the two parallel lines 3x - 2y + 4 = 0 and 3x - 2y - 8 = 0.
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Question 675307: Find the equation of the locus of the points which are equidistant from the two parallel lines 3x - 2y + 4 = 0 and 3x - 2y - 8 = 0.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the equation of the locus of the points which are equidistant from the two parallel lines
This is an equation of a straight line parallel and equidistant from given parallel lines
3x - 2y + 4 = 0 and 3x - 2y - 8 = 0
**
3x - 2y + 4 = 0
2y=3x+4
y=3x/2+2
..
3x - 2y - 8 = 0
2y=3x-8
y=3x/2-4
..
since equation is parallel to given lines, its slope is the same as that of given lines=3/2
equation: y=3x/2+b
y-intercept, b=mid point of y- intercepts of two given parallel lines=(2+(-4))/2=-2/2=-1
equation of the locus of the points which are equidistant from the two parallel lines: y=3x/2-1
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