SOLUTION: What is the equation of a line in slope intercept form that has the endpoints of (3,6)and (7,-2)?

Question 620573: What is the equation of a line in slope intercept form that has the endpoints of (3,6)and (7,-2)?

Found 2 solutions by jim_thompson5910, lwsshak3:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Note: is the first point . So this means that and .
Also, is the second point . So this means that and .

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

Reduce

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Distribute

Multiply

Add 6 to both sides.

Combine like terms.

So the equation that goes through the points and is

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What is the equation of a line in slope intercept form that has the endpoints of (3,6)and (7,-2)?
**
Standard form of equation for a straight line: y=mx+b, m=slope, b=y-intercept
For given problem:
slope of line=∆y/∆x=rise/run=(-2-6)/(7-3)=-8/4=-2
equation: y=-2x+b
solve for b using coordinates of either of given points, like (3,6)
6=-2*3+b
b=12
equation of line: y=-2x+12

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