Hi,

find the length of the sides of tiangle whose vertices are 

(1,4),

(-4,0)  D = sqrt(4^2 + 5^2) = sqrt(41)

(3,-3   D = sqrt(3^2 + -7^2) = sqrt(58)  longest side C

(1,4),  D = sqrt(-7^2 + 2^2) = sqrt(53)

 41 + 53 = 94 > 58

 If A, B and C are the sides of a triangle where C is the longest side, then we can say the following

i) If A^2+B^2 = C^2 is true, then we have a right triangle

ii) If A^2+B^2 > C^2 is the case, then we have an acute triangle.***** 

iii) If A^2+B^2 < C^2, then we have an obtuse triangle.

 

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