SOLUTION: Solve for x in the equation x + 1 = the square root of (the total of) x + 3. Thank you very much. Sabin

Question 59927: Solve for x in the equation x + 1 = the square root of (the total of) x + 3.
Thank you very much.
Sabin
Found 2 solutions by funmath, praseena:
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Hi Sabin,
Solve for x in the equation x + 1 = the square root of (the total of) x + 3.

(x+2)(x-1)=0
x+2=0 and x-1=0
x+2-2=0-2 and x-1+1=0+1
x=-2 and x=1
Check for extraneous soltuions.

x=1 checks out.

x=-2 is extraneous.
The only solution is x=1
Happy Calculating!!!

Answer by praseena(37) (Show Source): You can put this solution on YOUR website!
x+1=squr(x+3)
squaring on both sides, we have
(x+1)^2=x+3
expanding the expression (x+3)^2, we have,
x^2+2x+1=x+3
subtracting 3 on both sides,
x^2+2x-2= x
subtracting x from both sides
x^2+x-2=0, which is of the form x^2+bx+c=0, which can be solved using the formula,
here, a=1 b=1 and c= -2
substitute these values in the given formula we havw,
x =
which comes like this
x = -1+_sqrt(1+8)/2
= (-1+_sqrt(9)/2
= (-1+_3)/2
which is either, x = (-1+3)/2 or x=(-1-3)/2

so x=2/2=1 or x=-4/2=-2
so x=1 or-2

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