SOLUTION: A GARDENER MARKS OUT A NEW SECTION OF LAWN THAT IS SUPPOSED TO BE A RECTANGLE WITH SIDES OF LENGTH 15M AND 10M RESPECTIVELY. TO CHECK HE HAS MARKED OUT A RECTANGLE HE MEASURES THE

Algebra ->  Length-and-distance -> SOLUTION: A GARDENER MARKS OUT A NEW SECTION OF LAWN THAT IS SUPPOSED TO BE A RECTANGLE WITH SIDES OF LENGTH 15M AND 10M RESPECTIVELY. TO CHECK HE HAS MARKED OUT A RECTANGLE HE MEASURES THE       Log On


   

Question 58824: A GARDENER MARKS OUT A NEW SECTION OF LAWN THAT IS SUPPOSED TO BE A RECTANGLE WITH SIDES OF LENGTH 15M AND 10M RESPECTIVELY. TO CHECK HE HAS MARKED OUT A RECTANGLE HE MEASURES THE LENGTH OF THE DIAGONAL. HOW LONG SHOULD THIS BE?

Found 2 solutions by rcmcc, terbear1963:
Answer by rcmcc(152) About Me  (Show Source):
You can put this solution on YOUR website!
use pythagorean theorem to solve this question.a%5E2%2Bb%5E2=c%5E2+
to solve for c .sqrt%28a%5E2%2Bb%5E2%29=c+
sqrt%2815%5E2%2B10%5E2%29=c+
c=18
the cross length should be 18m.

Answer by terbear1963(43) About Me  (Show Source):
You can put this solution on YOUR website!
REMEMBER TO USE PATHAGOREAN'S FORMULA FOR SOLVING RIGHT TRIANGLES HERE!!!! A^2 + B^2 = C^2 NOW YOU CAN SOLVE THIS PROBLEM USING SIMPLE ALGEBRA. 15^2 + 10^2 = C^2 ----> 225 + 100 = C^2 ----> C^2 = 325 ----> C = (SQUARE ROOT OF 25)(SQUARE ROOT OF 13) ----> C = 5(SQUARE ROOT OF 13) I HOPE THIS HELPS YOU!? YOUR MATH FRIEND, TERRY (cats7051@yahoo.com)