# SOLUTION: what is the equation of the perpemndicular bisector of ab if a (-3,4) and b ( 7,-6)

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 Question 539556: what is the equation of the perpemndicular bisector of ab if a (-3,4) and b ( 7,-6)Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website! If the coordinates of A and B are ( x1, y1) and ( x2, y2) respectively, then the midpoint, M, of AB is given by the following formula ( -3 , 4 ) ( 7 , -6 ) M(x,y) = x= ( -3 + 7 )/ 2 y= ( 4 -6 )/ 2 x= 2 ,y= -1 Midpoint (2,-1) Slope of this line x1 y1 x2 y2 -3 * 4 7 -6 slope m = (y2-y1)/(x2-x1) ( -6 - 4 )/( 7 - -3 ) ( -10 / 10 ) m= -1 The slope of line perpendicular to this line will be 1 and it passes through (2,-1) m= 1 Plug value of the slope and point ( 2 , -1 ) in Y = m x + b -1.00 = 2 + b b= -1 - 2 b= -3 So the equation will be Y = x -3 m.ananth@hotmail.ca