SOLUTION: what is the equation of the perpemndicular bisector of ab if a (-3,4) and b ( 7,-6)

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Question 539556: what is the equation of the perpemndicular bisector of ab if a (-3,4) and b ( 7,-6)
Answer by mananth(12270) About Me  (Show Source):
You can put this solution on YOUR website!
If the coordinates of A and B are ( x1, y1) and ( x2, y2) respectively, then the midpoint, M, of AB is given by the following formula
( -3 , 4 ) ( 7 , -6 )
M(x,y) = %28x1%2Bx2%29%2F2%09%09%09 %09%28y1%2By2%29%2F2
x= ( -3 + 7 )/ 2 y= ( 4 -6 )/ 2
x= 2 ,y= -1
Midpoint (2,-1)
Slope of this line
x1 y1 x2 y2
-3 * 4 7 -6

slope m = (y2-y1)/(x2-x1)
( -6 - 4 )/( 7 - -3 )
( -10 / 10 )
m= -1

The slope of line perpendicular to this line will be 1
and it passes through (2,-1)
m= 1

Plug value of the slope and point ( 2 , -1 ) in
Y = m x + b
-1.00 = 2 + b
b= -1 - 2
b= -3
So the equation will be
Y = x -3
m.ananth@hotmail.ca